若圆x^2+y^2-2x-2y-16=0上恰有三点到直线l:ax-by=0的距离为2√2,则直线的倾斜角是

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若圆x^2+y^2-2x-2y-16=0上恰有三点到直线l:ax-by=0的距离为2√2,则直线的倾斜角是
若圆x^2+y^2-2x-2y-16=0上恰有三点到直线l:ax-by=0的距离为2√2,则直线的倾斜角是

若圆x^2+y^2-2x-2y-16=0上恰有三点到直线l:ax-by=0的距离为2√2,则直线的倾斜角是
圆的方程为(x-1)²+(y-1)²=(3√2)²
即圆心在(1,1),半径为3√2
为了保证恰有3个不同的点到直线的距离为2√2
则圆心到直线的距离等于3√2-2√2=√2
当a=0时,则b≠0,则圆心到直线l的距离为1-0=1

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