①﹙x+1/3﹚2=4②x2-x-6=0③y2-3y+1=0
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①﹙x+1/3﹚2=4②x2-x-6=0③y2-3y+1=0
①﹙x+1/3﹚2=4②x2-x-6=0③y2-3y+1=0
①﹙x+1/3﹚2=4②x2-x-6=0③y2-3y+1=0
解
(x+1/3)²=4
∴
x+1/3=±2
∴x=5/3
或x=-7/3
x²-x-6=0
(x-3)(x+2)=0
∴x=3
或x=-2
y²-3y+1=0
用公式法
△=b²-4ac=9-4=5
y=(3+√5)/2
或y=(3-√5)/2
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