x2-xy-6y2+x+7y-2
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x2-xy-6y2+x+7y-2
x2-xy-6y2+x+7y-2
x2-xy-6y2+x+7y-2
(x+2y-1)(x-3y+2)
方法:待定系数法
观察整式可设:
x^2-xy-6y^2+x+7y-2=(x+ay+b)(x+cy+d)
将式子展开比较两边系数可得
ac=-6;a+c=-1;bd=-2;b+d=1;ad+bc=7
解方程组得a=2 b=-1 c=-3 d=2
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