已知x/2=y/3=z/4,求x^2+2y^2+3z^2/xy+yz-zx的值
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已知x/2=y/3=z/4,求x^2+2y^2+3z^2/xy+yz-zx的值
已知x/2=y/3=z/4,求x^2+2y^2+3z^2/xy+yz-zx的值
已知x/2=y/3=z/4,求x^2+2y^2+3z^2/xy+yz-zx的值
问下:忘了加括号了吧,题目是不是应为(x^2+2y^2+3z^2)/(xy+yz-zx),如果是,则解为:
x:y:z=2:3:4,不妨设x=2a,y=3a,z=4a,(x^2+2y^2+3z^2)/(xy+yz-zx)=(4a^2+2*9a^2+3*16a^2)/(6a^2+12a^2-8a^2)=(70a^2)/(10a^2)=7
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