x=5 x+5y-2z=-4 4x-3y+2z=1
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x=5 x+5y-2z=-4 4x-3y+2z=1
x=5 x+5y-2z=-4 4x-3y+2z=1
x=5 x+5y-2z=-4 4x-3y+2z=1
后两式相加后将x代入,解的y,再将x y代入二或三式得z 这里用的是消元法
(4x-2y-z)-{5x-[8y-2z-(x-2y)]-x-(3y-10z)}=?
(4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuaihuajian
x+y=5 2x+3y-z=9 x-y+z=4
设|x|-|y|+|z|=|x+y+z|,且|x+y|=4,|y+z|=5,|y|=3,求(x-y-z)^2的值
(4x-2y-z)-{5x-[8y-2z-(x+y)]-2(3y-10z)}=?好难啊
(x+y):(y+z):(z+x)=3:4:5 3x+y-z=-4已知(x+y):(y+z):(z+x)=3:4:5 ;3x+y-z=-4求x y z
已知:4x-5y+2z=0 x+4y-3z=0则:(x*x+y*y+z*z)/(x*y+y*z+z*x)=____.
{5x-3y+z=2{5x+2y-4z=3{-5x+y-z=2 {x-y-z=-1{3x+5y+7z{4x-y+2x=-1
x:y=2:3 x:z=5:4 x+y+z=33
3x-2y+z=4 x+y-z=5 4x-4y+3z=27
{ 5x-3y+z=25x+2y-4z=3-5x+y-z=2
x+y+z=4,x+2y-z=4,3x-y+4z=5
已知(x+2y)/3=(y+3z)/4=(z+5x)/5,则x:y:z=
已知x+2y/3=y+3z/4=z+5x/5,则x:y:z=?
已知x+2y/3=y+3z/4=z+5x/5,则x:y:z=
x-y+z=-1 5x+2y-z=6 4x-3y+2z=-5
x:y=3:2 y:z=5:4 x+y+z=66
x:y=3:2 y:z=5:4 x+y+z=66