[(2x+y)(x-3y)+y(x+3y)]÷(2x)计算,

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[(2x+y)(x-3y)+y(x+3y)]÷(2x)计算,
[(2x+y)(x-3y)+y(x+3y)]÷(2x)计算,

[(2x+y)(x-3y)+y(x+3y)]÷(2x)计算,
(2x+y)(x-3y)=2x(x-3y)+y(x-3y);y(x-3y)+y(x+3y)=2xy;所以2x(x-3y)+2xy=2x(x-3y+y)=2x(x-2y);
2x(x-2y)÷(2x)=x-2y

十字交叉法会不？
2X Y
X -3Y
---------------------------
2X^2 -6XY+XY -3Y^2 ------> [(2X^2-5XY-3Y^2)+(XY+3Y^2)]/(2X)
=[2X^2-4XY ]/(2X)=X-2Y

分母一直是2x，我先化开分子=2x平方-6xy+xy-3y平方+xy+3y平方=2x平方-4xy. 加上分母一起化简，最后=x-2y

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