lim(x->1)(x^(n)-1)/x-1)=?n为正整数,怎么算得,
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lim(x->1)(x^(n)-1)/x-1)=?n为正整数,怎么算得,
lim(x->1)(x^(n)-1)/x-1)=?n为正整数,怎么算得,
lim(x->1)(x^(n)-1)/x-1)=?n为正整数,怎么算得,
lim(x->1)(x^(n)-1)/x-1)=lim(x->1)(x^(n-1+x^(n-2)+……+x+1)(x-1)/x-1)=lim(x->1)[x^(n-1)+x^(n-2)+……+x+1]=n
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