设A=2x²-3xy+y²-x+2y,B=4x²-6xy+2y²-3x-y,若│x-2a│+(y+3)²=0,且B-2A=a,求A

设A=2x²-3xy+y²-x+2y,B=4x²-6xy+2y²-3x-y,若│x-2a│+(y+3)²=0,且B-2A=a,求A
设A=2x²-3xy+y²-x+2y,B=4x²-6xy+2y²-3x-y,若│x-2a│+(y+3)²=0,且B-2A=a,求A

设A=2x²-3xy+y²-x+2y,B=4x²-6xy+2y²-3x-y,若│x-2a│+(y+3)²=0,且B-2A=a,求A
因为,│x-2a│+(y+3)²=0
由非负性可得,
x-2a=0且y+3=0
解得,x=2a,y=-3
又,B-2A=-x-5y=a
所以,
2(x+5y)+x=0
即,3x+10y=0
将y＝-3代入,得3x-30=0
解得,x=10
所以,
A=2x²-3xy+y²-x+2y
=200+90+9-10-6
=299-16
=283