证明lim(x->1)x^2/(x+1) =1/2lim (x→1)x^2/(x+1)= lim (x→1)[(x^2-1)/(x+1)+1/(x+1)] = lim (x→1)[x-1+1/(x+1)]=1/2这样做对吗
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证明lim(x->1)x^2/(x+1) =1/2lim (x→1)x^2/(x+1)= lim (x→1)[(x^2-1)/(x+1)+1/(x+1)] = lim (x→1)[x-1+1/(x+1)]=1/2这样做对吗
证明lim(x->1)x^2/(x+1) =1/2
lim (x→1)x^2/(x+1)= lim (x→1)[(x^2-1)/(x+1)+1/(x+1)] = lim (x→1)[x-1+1/(x+1)]=1/2这样做对吗
证明lim(x->1)x^2/(x+1) =1/2lim (x→1)x^2/(x+1)= lim (x→1)[(x^2-1)/(x+1)+1/(x+1)] = lim (x→1)[x-1+1/(x+1)]=1/2这样做对吗
没必要这样做
直接代入即可
lim(x→1)x^2/(x+1)=1^2/(1+1)=1/2
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