x-(x-1)/2和2-(x+2)/5互为相反数,x=?x应该=-7啊!怎么解?O

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x-(x-1)/2和2-(x+2)/5互为相反数,x=?x应该=-7啊!怎么解?O
x-(x-1)/2和2-(x+2)/5互为相反数,x=?
x应该=-7啊!怎么解?
O

x-(x-1)/2和2-(x+2)/5互为相反数,x=?x应该=-7啊!怎么解?O
[x-(x-1)/2]+[2-(x+2)/5]=0
10X-5(X-1)+20-2(X+2)=0
10X-5X+5+20-2X-4=0
3X+21=0
3X=0-21
3X=-21
X=-7

相反数就是说相加等于0.先把两个式子通分

x-(x-1)/2+2-(x+2)/5=0
10x-5x+5+20-2x-2x-4=0
3x=-21
x=-7

[x-(x-1)/2]+[2-(x+2)/5]=0
10x-5x+5+20-2x-4=0
3x=-21
x=-7

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