m/(x+1)-n/(x+2)=1/(x+1)(x+2),mn为常数,求mn的值.
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m/(x+1)-n/(x+2)=1/(x+1)(x+2),mn为常数,求mn的值.
m/(x+1)-n/(x+2)=1/(x+1)(x+2),mn为常数,求mn的值.
m/(x+1)-n/(x+2)=1/(x+1)(x+2),mn为常数,求mn的值.
m/(x+1)-n/(x+2)=1/(x+1)(x+2)
[(m(x+2)-n(x+1)]/(x+1)(x+2))=1/(x+1)(x+2)
[(m-n)x+2m-n)]/(x+1)(x+2))=1/(x+1)(x+2)
(m-n)x+2m-n)=1
m-n=0,2m-n=1
m=n=1
mn=1
m/(x+1)-n/(x+2)=1/(x+1)(x+2)
(m(x+2)-n(x+1)/
(x+1)(x+2)) =1/(x+1)(x+2)
(m(x+2)-n(x+1)/
(x+1)(x+2)) =1/(x+1)(x+2)
(m(x+2)-n(x+1)/1
m-n=0,2m-n=1
m=n=1
mn=1
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