(3X+4)(3X-4)-(2X+3)(3X-2)

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/17 01:34:14

(3X+4)(3X-4)-(2X+3)(3X-2)
(3X+4)(3X-4)-(2X+3)(3X-2)

(3X+4)(3X-4)-(2X+3)(3X-2)
(3X+4)(3X-4)-(2X+3)(3X-2) =(3X) 2 —4 2 —(6X 2 —4X+9X-6) =9X 2 —16—6X 2 —5X+6 =3X 2 —5X—10

前部分平方差公式,(3X+4)(3X-4)=3x*3x-4*4=9x^2-16 后部分只有把括号展开了,(2X+3)(3X-2)=6x^2+5x-6 最后结果 3x^2-5x-10

*-----------------------------------------------*| 6 4 X | 8 X X | X X 5 || X X X | X X X | X 7 8 || X X X | X X X | X X X ||---------------+---------------+--------------- || X X X | X X X | 5 1 X || X X X | X 6 X | X X X || 8 X X | 3 5 X | 2 X X || x+2/x+1-x+3/x+2-x+4/x+3+x+5/x+4 (x+3x+5x...+2009x)-(2x+4x+6x+...+2010x) x^5-x^4+x^3-x^2+x-1 求一个数独答案X X X 9 X X X 8 2 X 6 3 X X 1 4 X 99 X 8 X X X X X XX X X 6 7 X 3 X XX 4 6 X 5 X 2 9 XX X 7 X 2 3 X X XX X X X X X 7 X 17 X 4 3 X X 6 2 X6 3 X X X 7 X X X 一个“整式的乘法”的问题请先阅读下列解题过程,再仿做下面的问题.已知X*X + X - 1=0,求X*X*X + 2*X*X + 3的值.解X*X*X + 2X*X +3=X*X*X +X*X -X +X*X +X +3=X{X*X +X -1} +X*X +X -1 +4=0+0+4=4+ x + X*X + X*X*X=0.+ X*X + X*X*X 难倒爱因斯坦的九宫格X 7 X | X 8 1 | X X X |X X X | X 4 X | 7 5 9 |X X 5 | 7 X 9 | X 1 4 |5 X X | X X 8 | 3 9 X |3 9 6 | 4 X 7 | X X 2 |X 8 7 | 9 X X | X X X |4 X X | 6 X 5 | X X X | X X 4 | X X 1 |2 X X | X X X | X X X | X 3 X | X X X |X 6 x+2x+3x+4x+5x+6x+7x+8x+9x=9x-8x-7x-6x-5x-4x-3x-2x-x.x等于多少? 如下9*9宫图如何填x x x 1 x x x 2 9x x 5 x x x x x 4x 6 8 x x x x x xx x x 7 x x 5 x xx 2 x x 6 x x 8 xx x 3 x x 9 x x xx x x x 5 x 1 6 x 4 x x x 3 x x x x 7 x x x x 2 x x x 解九宫格题目(X为未知数)9 X 2 X 7 X 8 X XX X 4 X X 9 X 6 X1 3 X 5 X X X X 24 X X 8 5 X X 1 XX 8 9 4 X 1 6 7 XX 1 X X 3 6 X X 88 X X X X 2 X 3 6X 5 X 6 X X 9 X XX X 7 X 4 X 2 X 1 (2x-6)/(4-4x+x^2)/(x+3)*(x^2+x-6)/(3-x) [x^2+2x-8/x^3+2x^2+x]÷[(x-2/x)×(x+4/x+1)]化简[x^2+2x-8/x^3+2x^2+x]÷[(x-2/x)×(x+4/x+1)]化简 计算:[(x^2 - 4)/(x^2 - x - 6) + (x+2)/(x-3)] / (x+1)/(x-3) a+x/x+1 ,x/x^2-2x-3 ,a/x^2+4x+3 (x-3/x-2)-(x-2/x-1)=(x-5/x4) -(x-4/x-3) lim(x+1)^x+1(x+3)^x+3/x^2x+4 x趋于无穷 (x-1)/(x+3x+2)+6/(2+x-x)-(10-x)/(4-x) x-2x+3x-4x+5x.+99x-100x=25求解