1/(m-2) =m/3 =6/2m 如何解得m?
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/15 14:46:43
1/(m-2) =m/3 =6/2m 如何解得m?
1/(m-2) =m/3 =6/2m 如何解得m?
1/(m-2) =m/3 =6/2m 如何解得m?
1/(m-2)=m/3
m(m-2)=3
m²-2m-3=0
(m-3)(m+1)=0
得:x=3或x=-1
m/3=6/(2m)
2m²=18
m²=9
m=3或m=-3
则:m=3
(m+3m+5m+...+2015m)-(2m+4m+6m+...+2014m)=
m-2m-3m+4m-5m-6m+7m.2004m=?
(m+3m+5m.+2013m)-(2m+4m+6m+.+2012m)=?
m^2+m-6/m^2+2m+1÷m+3/m^+m·m^2-1/2-m 其中m=-1/2
(m+3m+5m+7m+.+2009m)-(2m-4m-6m-.-2008m)=?
求1-2m+m^2/m-1 — 根号(m^2-2m+1)/m^2-m如题已知m=1/2+根号3
m^2+m-1=0,则m^3+2m^2+1等于?如题
m*m-5m-1=0则2m*m-5m+1/m*m
已知m*m+m-1=0,求m*m*m+2m*m-2005
先化简 再求值(3+m)(3-m)+m(m-6)-7,其中m=1/2
计算(m+3m+5m……+2009m)—(2m+4m+6m+2008m)=
计算:(m+3m+5m+…+2015m)-(2m+4m+6m+…+2014m)=
计算(m+3m+5m+.+2009m)-(2m+4m+6m+.+2010m)=多少
(m+3m+5m+...+2011m)-(2m+4m+6m+...+2012m)=多少
计算:(m+3m+5m+…+2011m)-(2m+4m+6m+…+2010m)=
(m+3m+5m+...+2011m)-(2m+4m+6m+...+2012m)=多少
计算(m+3m+5m+...+2011m)-(2m+4m+6m+...+2010m)=
m-2m-3m+4m-5m-6m=m-2m-3m+4m-5m-6m+···+2002m-2003m-2004m