[(x的平方-2xy+y的平方)+(3x+3y)+2]除以(x-y+1)

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[(x的平方-2xy+y的平方)+(3x+3y)+2]除以(x-y+1)
[(x的平方-2xy+y的平方)+(3x+3y)+2]除以(x-y+1)

[(x的平方-2xy+y的平方)+(3x+3y)+2]除以(x-y+1)
题目是不是这样的:
[(x的平方-2xy+y的平方)+(3x-3y)+2]除以(x-y+1)
=[(x-y)^2+3(x-y)+2]/(x-y+1)
=(x-y+1)(x-y+2)/(x-y+1)
=x-y+2

题有误,应为:[(x的平方-2xy+y的平方)+(3x-3y)+2]除以(x-y+1)
[(x的平方-2xy+y的平方)+(3x-3y)+2]除以(x-y+1)
=[(x-y)^2+3(x-y)+2]/(x-y+1)
=(x-y+1)(x-y+2)/(x-y+1)
=x-y+2