2011(2X+Y)+(X-2Y)=1 (2X+Y)+2011(X-2Y)=2011 这题二元一次方程怎么做
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2011(2X+Y)+(X-2Y)=1 (2X+Y)+2011(X-2Y)=2011 这题二元一次方程怎么做
2011(2X+Y)+(X-2Y)=1 (2X+Y)+2011(X-2Y)=2011 这题二元一次方程怎么做
2011(2X+Y)+(X-2Y)=1 (2X+Y)+2011(X-2Y)=2011 这题二元一次方程怎么做
可以用换元法解
设2x+y=m,x-2y=n,则原式变为
2011m+n=1①
m+2011n=2011②
解①②得:m=0,n=1
所以2x+y=0
x-2y=1
解得:x=1/5,y=-2/5
x-y/x-x+y/y-(x+y)(x-y)/y² y/x=2
[(x-y)^2+(x+y)(x-y)]÷2x,其中x=2011y=-1
[(x-y)^2+(x+y)(x-y)]÷2x,其中x=2011y=1
2y(x+二分之一y)-[(x+y)(x-y)+2y(y+x)],其中|x-1|=2
(x-y)(x+y)-(x+y)^2+2y(y-x),其中x=1,y=3.
已知x+y=a,2x-y=-2a,求[(x/y-y/x)/(x+y)-x(1/x-1/y)]/[(x+1)/y]的值
若2/x-1/y=3,求[y/x-y/x-y(x-y/x-x+y)]/x-2y/x的值
x+2y=2x+y+1=7x-y 求:2x-y?
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