(x+2y)^2+4(x+2y)+3怎么解
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(x+2y)^2+4(x+2y)+3怎么解
(x+2y)^2+4(x+2y)+3怎么解
(x+2y)^2+4(x+2y)+3怎么解
把x+2y看做一项,用十字相乘法来解,把3变成3X1,而3+1刚好是一次项系数4
(x+2y)^2+4(x+2y)+3=(x+2y+3)(x+2y+1)
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