若 x+y=8,x^2y^2=4,则x^2+y^2=
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/15 17:25:35
若 x+y=8,x^2y^2=4,则x^2+y^2=
若 x+y=8,x^2y^2=4,则x^2+y^2=
若 x+y=8,x^2y^2=4,则x^2+y^2=
若 x+y=8,x^2y^2=4
则,xy=2,(-2)
1当xy=2时
x^2+y^2
=(x+y)^2-2xy
=8^2-2*2
=64-4
=60
2.当xy=-2时
x^2+y^2
=(x+y)^2-2xy
=8^2-2*(-2)
=64+4
=68
x-y/x-x+y/y-(x+y)(x-y)/y² y/x=2
若X+Y=8,(X-Y)^2=4,则X^2+Y^2=
若x,y,z成等差数列,则(z-x)^2-4(x-y)(y-x)=
若x-y=1 化简(x+y)(x^2+y^2)(x^4+y^4)(x^8+y^8)(x^16+y^16)
若x+y=4,则多项式1/2(x+y)+4(x-y)-3(x-y)-3/2(x+y)-x+y值是()
若f(x+y,y/x)=x^2-y^2,则F(X,Y)=
若(x-y)/(x+y)=3 则(x+2y)/(6x-7y)等于
若2x=3y,则(x*x+y*y)/x*x=?
若(x*x+y*y)(x*x+y*y)-4x*x*y*y=0,求代数式(x*x+5xy+y*y)/(x*x+2xy+y*y)的值
若x-y不等于0,2x-3y=0,则分式(10x-11y)/(x-y)的值是()?(10x-11y)/(x-y) =[(8x-8y)+(2x-3y)]/(x-y) =8为什么8X-8Y=8?(10x-11y)/(x-y)=[(8x-8y)+(2x-3y)]/(x-y)=8+(2x-3y)]/(x-y)=8+0=8
[(x+2y)(x-2y)-(x-2y)^2+8y(x+y)]除以4x=
已知x*x+4x+y*y-2y+5=0,则x*x+y*y=?
若2x-3y+4=0则x(x*x-1)+x(5-x*x)-6y+7
(x-y) (x-2y)+(x+2y) (x-3y)-2(x-3y) (x-4y)=
(x-4y)(2x+y)=
若x=2012,y=2013,则(x+y)×[(x^2+y^2)/x^4-y^4)]
若5x+3y=3x+4y=x+2y+6,则x+y=___
若x^2+y^2-6x+8y+25=0 则y/x-x/y的值是