1/log1/41/9+1/log1/51/3= 急

1/log1/41/9+1/log1/51/3= 急
1/log1/41/9+1/log1/51/3= 急

1/log1/41/9+1/log1/51/3= 急
=log(1/3)1/2+log(1/3)1/5 =log(1/3)1/10 f(x)=log(1/3)x在定义域上递减.因为1/27<1/10<1/9,所以 2=log(1/3)1/9<log(1/3

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