(3x)²+10²=(7x-10)²
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(3x)²+10²=(7x-10)²
(3x)²+10²=(7x-10)²
(3x)²+10²=(7x-10)²
9x²+100=49x²-140x+100
40x²-140x=0
20x(2x-7)=0
x1=0,x2=7/2
(3x)²+10²=(7x-10)²
(3x)²-(7x-10)² +10²=0
(3x-7x+10)(3x+7x-10)+100=0
(10-4x)(10x-10)+100=0
(5-2x)(x-1)+5=0
-2x^2+7x-5+5=0
x(-2x+7)=0
x=0 或 x=7/2
9X²+100=49X²-140X+100
49X²-9X²-140X+100-100=0
40X²-140X=0
X(40X-140)=0
∴X=0 或40X-140=0
X1=0 X2=3.5