x+2y+3z=2,3x+y+2z=3,2x+3y+z=4,求x+y+z的值
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x+2y+3z=2,3x+y+2z=3,2x+3y+z=4,求x+y+z的值
x+2y+3z=2,3x+y+2z=3,2x+3y+z=4,求x+y+z的值
x+2y+3z=2,3x+y+2z=3,2x+3y+z=4,求x+y+z的值
x+2y+3z=2
3x+y+2z=3
2x+3y+z=4
3式相加
6x+6y+6z=9
x+y+z=2/3
2X+3Y+Z=38
3X+4Y+2Z=56
4X+5Y+Z=66
1式减3式 得:2x+2y=8
1式*2-2式得:2x+3y=20 得y=-8 带回式子 x=12
再带 z=38
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
已知(x+y)(x+z)=x,(y+z)(y+x)=2y,(z+x)(z+y)=3z,求x,y,z
证明 :x/(y+z)+y/(z+x)+z/(x+y)>=3/2其中 x,y,z>0
x/2=y/3=z/5 x+3y-z/x-3y+z
x+2y=3x+2z=4y+z 求x:y:z
x+y/2=z+x/3=y+z/4 x+y+z=27
若x+y+z=3y=2z,则x/x+y+z=?
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x+y+z=6 x+2y+3z=14 y+1=z
X/10=Y/8=Z/9,则X+Y+Z/2Y-3Z
X=3z X+y+z=12 X+2y-2z=10
2x+z=10 x+y-z=4 3x-y-z=0
x=y/z=z/3,x+y+z =12,求2x+3y+4z是多少,
若|x+3|+|y-2|+|2×z+1|=0求(x×z-y×z)(y-x+z)的值
matlab解对数方程组[x,y,z]=solve('0.29744*x/(3+0.1*x+y+z)=(log10((3+x+y+z)/(3+0.1*x+y+z)))^2','0.79*x/(3+0.1*y+z)=(log10((3+x+y+z)/(3+0.1*x+y+z)*(3+y+z)/(3+0.1*y+z)))^2','1.25*x/(3+0.1*z)=(log10((3+x+y+z)/(3+0.1*x+y+z)*(3+y+z)/(3+0.*1y+z)*(3+z)/