(x+1)(x+2)(X+3)(x+6)+x的平方

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(x+1)(x+2)(X+3)(x+6)+x的平方
(x+1)(x+2)(X+3)(x+6)+x的平方

(x+1)(x+2)(X+3)(x+6)+x的平方
原式
=[(x+1)(x+6)][(x+2)(x+3)]+x²
=[(x²+6)+7x][(x²+6)+5x]+x²
=(x²+6)²+12x(x²+6)+35x²+x²
=(x²+6)²+12x(x²+6)+36x²
=(x²+6x+6)²

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