2[(x^3)-1]×3x^2=0,求x?提供下一元二次函数的求x公式?2+(2/x^3)=0,求x?3/2(根号立方下x^2),求导数?
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/06 07:11:13
2[(x^3)-1]×3x^2=0,求x?提供下一元二次函数的求x公式?2+(2/x^3)=0,求x?3/2(根号立方下x^2),求导数?
2[(x^3)-1]×3x^2=0,求x?
提供下一元二次函数的求x公式?
2+(2/x^3)=0,求x?
3/2(根号立方下x^2),求导数?
2[(x^3)-1]×3x^2=0,求x?提供下一元二次函数的求x公式?2+(2/x^3)=0,求x?3/2(根号立方下x^2),求导数?
问题一:2[(x³)-1]×3x²=0,求x?
x₁= x₂= x₃= 1 (这是实数范围内的解);
x₄= x5 = 0
x³ = 1 = e^(2kπi) (k=0,±1,±2,±3,...)
x = e^(⅔kπi)
虚数范围内的解是:
x₁= 1 [k=0]
x₂= ½ ± i(√3)/2 [k=±1]
x₃= -½ ± i(√3)/2 [k=±2]
问题二:提供下一元二次函数的求x公式?
y = ax² + bx + c
ax² + bx + c - y = 0
x = [-b ± √(b²-4ac+4ay)]/2b
问题三:2+(2/x³)=0,求x?
2/x³ = -2
x³ = -1
x₁= x₂= x₃= -1 (这是实数范围内的解);
x³ = -1 = e^[(2k+1)πi] (k=0,±1,±2,±3,...)
x = e^[⅓(2k+1)πi]
虚数范围内的解是:
x₁= ½ + i(√3)/2 [k=0]
x₂= -1 [k=1]
x₃= ½ - i(√3)/2 [k=-1]
x₄= -½ - i(√3)/2 [k=2]
x5 = x₂= -1 [k=-2]
x6 = x₁= ½ + i(√3)/2 [k=3]
x7 = -½ + i(√3)/2 [k=-3]
综合得解集:
-1,
±½ ± i(√3)/2
问题四:3/2(根号立方下x^2),求导数?
y = (3/2)x^(2/3)
dy/dx = (3/2)×(2/3)x^(-1/3) = 1/x^(⅓)