y=1+log2^x/2+(log2^x)^2的值域log2^x=t 求反解法做

y=1+log2^x/2+(log2^x)^2的值域log2^x=t 求反解法做
y=1+log2^x/2+(log2^x)^2的值域
log2^x=t 求反解法做

y=1+log2^x/2+(log2^x)^2的值域log2^x=t 求反解法做
令log2^x=t
y=1+t/2+t^2
=(t+1/4)^2+15/16
∵t∈R
∴y∈[15/16,+∞）