2x^2+3y^2-8x+6y+11=0求x+y=
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2x^2+3y^2-8x+6y+11=0求x+y=
2x^2+3y^2-8x+6y+11=0求x+y=
2x^2+3y^2-8x+6y+11=0求x+y=
配方:2(x-2)^2+3(y+1)^2=0
两个非负数之和为0 则它们都为0
所以x-2=0
y+1=0
所以x=2
y=-1
x+y=1
由题中方程得
2(x-2)^2+3(y+1)^2=0
故要使等式成立就要x-2=0且y+1=0
故x=2,y=-1
故x+y=1
【2(x-y)^3-8(x-y)^2(x+y)+6y(x-y)^2】/2(x-y)^2=
y-3x=2,y-5x=4,y-7x=6,y-9x=8,y-11x=0方程组,无
【2(x-y)(x-y)(x-y)-8(x-y)(x-y)(x+y)+6y(x-y)(x-y)]/2(x-y)(x-y)
若x-y不等于0,2x-3y=0,则分式(10x-11y)/(x-y)的值是()?(10x-11y)/(x-y) =[(8x-8y)+(2x-3y)]/(x-y) =8为什么8X-8Y=8?(10x-11y)/(x-y)=[(8x-8y)+(2x-3y)]/(x-y)=8+(2x-3y)]/(x-y)=8+0=8
x*x+2x-y*y+6y-8=0,x+y不等于2,求x-y的值
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{x+y=1 ,xy=-6{x(2x-3)=0,y=x²-1{(3x+4y-3)(3x+4y+3)=0,3x+2y=5{(x-y+2)(x+y)=0,x²+y²=8{(x+y)((x+y-1)=0,(x-y)(x-y-1)=0
[2(x-y)^5-8(x-y)^2(x+y)+6y(x-y)^2]÷2(x-y)^2[2(x-y)^3-8(x-y)^2(x+y)+6y(x-y)^2]÷2(x-y)^2
x-y/x-x+y/y-(x+y)(x-y)/y² y/x=2
3x+2=y 5x+4=y 7x+6=y 9x+8=y 11x=y 联立方程 有的话
3x+2=y 5x+4=y 7x+6=y 9x+8=y 11x=y
3x+2=y 5X+4=Y 7X+6=Y 9X+8=y 11x=y要如何计算
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12y(x-y)^2-8(x-y)^3=?
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