y=√x平方+1,求dy

y=√x平方+1,求dy
y=√x平方+1,求dy

y=√x平方+1,求dy
y=√x平方+1
dy=1/2*1/(√x平方+1)*2x*dx
=x*dx*/√x平方+1

y=(x^2+1)^(1/2)
y'=(1/2)(x^2+1)^(1/2-1)*(x^2)'
=x*(x^2+1)^(-1/2)
=x/√(x^2+1)
dy=xdx/√(x^2+1)

dy=d(√x^2+1)=[x/(√x^2+1)]dx