f(x) = x^2(4-2x^2)的最大值是?(0

f(x) = x^2(4-2x^2)的最大值是?(0
f(x) = x^2(4-2x^2)的最大值是?
(0

f(x) = x^2(4-2x^2)的最大值是?(0
x²>=0
则令a=x²>=0
y=f(a)=a(4-2a)
=-2a²+4a-2+2
=-2(a-1)²+2
则a=1,最大值=2

t=x^2>=0
y=t(4-t)最大值=4