若2X+3Y-1=Y-X-8=X+6,则2XY=()
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若2X+3Y-1=Y-X-8=X+6,则2XY=()
若2X+3Y-1=Y-X-8=X+6,则2XY=()
若2X+3Y-1=Y-X-8=X+6,则2XY=()
2X+3Y-1=Y-X-8
3X+2Y=-7
Y-X-8=X+6
2X-Y=-14
3X+2Y=-7
2X-Y=-14
解方程组得
X=-5
Y=4
2XY=2*(-5)*4=-40
这也就是二元一次方程组,X=-5 Y=4 则 2XY=--40
2X+3Y-1=X+6
X=7-3Y
代入Y-X-8=X+6
得,Y-2X=14
Y-14+6Y=14
则,7Y=28
Y=4
X=-5
那么2XY=-40
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