y=(x+1)^0.5-(x-1)^0.5 怎么求导

mathematica软件,已知y[x],Y=f1(x),X(x)=f2(x),如何plot Y[X]?y[x_] := x + 9.81/2*x*xk=1X[x] = x - k*y'[x]/(1 + (y'[x])^2)^0.5Y[x] = y[x] + k/(1 + (y'[x])^2)^0.5Plot[{y[x],Y[X],},{x,0,2}] 已知实数x,y满足方程x*x+y*y-4x+1=0.求y-x的最大值 x>=1,x-y y=x-1(x 设x.y满足条件y>=0.X-Y+1>=0.x+y-3 matlab画二元函数图像z = (x/(x+y) + 1.96*1.96/(2*(x+y)) - 1.96 * ((x/(x+y)*(1-x/(x+y))+1.96*1.96/(4*(x+y)))/(x+y))^0.5)/(1+1.96*1.96/(x+y))该怎么画 求导 y=[x/(1+x)]^x y'-(1/x)y=xe^-x 1/2x=0.5y则y/x()/(). 1/2x=0.5y则y/x()/(). z=0.015x*x+y*x*0.05+(1-x-y)*2.5*(x+y) x>0.35.xy>0.70x+y y=(x-1/x)/2反函数为y=x+(x^2+1)^0.5 已知x+y=a,2x-y=-2a,求[（x/y-y/x)/(x+y)-x(1/x-1/y)]/[(x+1)/y]的值 y=2x^2-4x-8 y=0.5x^2+2x-1 x.y都是自然数,且x(x-u)-y(y-x)+12,求x.y得值快1且x(x-y)-y(y-x)=12 若2/x-1/y=3,求[y/x-y/x-y(x-y/x-x+y)]/x-2y/x的值 y'/y=1/x (x-5y)(-x-5y)-(-x-5y)^2其中x=-1,y=-0.5