(x-6)(y+12)=(x+4)(y-4)=xy 谁来教教我?
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(x-6)(y+12)=(x+4)(y-4)=xy 谁来教教我?
(x-6)(y+12)=(x+4)(y-4)=xy
谁来教教我?
(x-6)(y+12)=(x+4)(y-4)=xy 谁来教教我?
应把原方程拆成两个新方程(x-6)(y+12)xy和(x+4)(y-4)=xy
再分别解这两个方程,会发现xy项消没了,再将化减后的两个方程连立,从而组成一个二元一次方程组,这样你就会做了.Αガ
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8(x-y)=3(x+y)-12 6(x+y)=4(2x-y)+16
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x+y/2+x-y/3=6,4(x+y)-3(x-y)=-20
{(x+y)/2+(x-y)/3=6 4(x+y)-3(x-y)=-20
4(x+y)-3(x-y)=-20,2/x+y+3/x-y=6
(x+y)/2- x-y/2=6 3(x+y)=4(x-y)
x+y/3+x-y/2=6 4(x+y)-2(x-y)=40
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