1/(1+2+3)+1/(4+5+6)+.+1/(100+101+102) =?帮我算下答案帮我也算出来啊

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/17 19:47:44

1/(1+2+3)+1/(4+5+6)+.+1/(100+101+102) =?帮我算下答案帮我也算出来啊
1/(1+2+3)+1/(4+5+6)+.+1/(100+101+102) =?
帮我算下
答案帮我也算出来啊

1/(1+2+3)+1/(4+5+6)+.+1/(100+101+102) =?帮我算下答案帮我也算出来啊
1/(1+2+3)=1/3*2 1/(4+5+6)=1/3*5 1/(100+101+102)=1/3*101
1/(1+2+3)+1/(4+5+6)+.+1/(100+101+102)
=1/3(1/2+1/5+1/8.+1/101) 括号里为通项为1/(an*3-1)的数列

似乎没法化简了

1.(1+1/2+1/3+1/4)*(1/2+1/3+1/4+1/5)-(1+1/2+1/3+1/4+1/5)*(1/2+1/3+1/4)=2.(1+1/2+1/3+1/4+1/5)*(1/2+1/3+1/4+1/5+1/6)-(1+1/2+1/3+1/4+1/5+1/6)*(1/2+1/3+1/4+1/5)= (1+2/1)(1+4/1)(1+6/1).(1+10/)(1-3/1)(1—5/1).(1-9/1) 1/(1*3)+1/(2*4)+1/(3*5)+1/(4*6)+...+1/(8*10)=? (-1/4)+5/6+2/3-1/2 1/6【1/4{1/3(1/2X-1)+3}+5】=1 1/2 + 1/6 + 1/12 + 1/20 + 1/30+ 1/42 + 1/56 + 1/72=(1+ 1/2+ 1/3+ 1/4+ 1/5)×(1/2+ 1/3+ 1/4+ 1/5+ 1/6)-(1+ 1/2+ 1/3+ 1/4+1/5+ 1/6)×(1/2+ 1/3+ 1/4+ 1/5) 1/(1×2×3)+1/(2×3×4)+1/(4×5×6)、、、、+1/(48×49×50) 1/2*1/3+1/3*1/4+1/4*1/5+1/5*1/6 (简便方法) (1-1/2)+ (1/3-1/4)+ (1/5-1/6)...+ (1/99-1/100)=? 巧算:(1/2+1/3)-(1/3+1/4)+(1/4+1/5)-(1/5-1/6)-(1/6+巧算:(1/2+1/3)-(1/3+1/4)+(1/4+1/5)-(1/5-1/6)-(1/6+1/7)-(1/7+1/8) 1 3/4-5/6-(+1 1/6)-(-1/2) 2/3,1,6/5,4/3,( ),3/2 (1/2+1/3+1/4+1/5+1/6+.+1/2013)*(1+1/2+..+1/2012)-(1+1/2+1/3+1/4+...+1/2013)*(1/2+.+1/2012)(1/2+1/3+1/4+1/5+1/6+...+1/2013)*(1+1/2+1/3+1/4...+1/2012)-(1+1/2+1/3+1/4+...+1/2013)*(1/2+1/3+1/4+...+1/2012) (1)1+1/2+1/3+1/4+1/5+1/6+1/7+1/14+1/28 几道巧算题、求解答啊啊、急【1+(1/2)+(1/3)+(1/4)】*【(1/2)+(1/3)+(1/4)+(1/5) 】-【1+(1/2)+(1/3)+(1/4)+(1/5)】*【(1/2)+(1/3)+(1/4)】【1+(1/2)】*【1+(1/4)】*【1+(1/6)】·····【1+(1/10)】*【1- 1234567654321*(1+2+3+4+5+6+7+6+5+4+3+2+1) (1+1*3分之1)(1+2*4分之1)(1+3*5分之1)(1+4*6分之1)…(1+9*11分之1)(1+1*3分之1)*(1+2*4分之1)*(1+3*5分之1)*(1+4*6分之1)…(1+9*11分之1)=? (1 3 5 .1991)-(2 4 6 .1990)